Gobang native JavaScript sharing

osc_xsd7kks3 2020-11-09 12:58:28
gobang native javascript sharing


1.HTML part

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, height=device-height, initial-scale=1.0, user-scalable=no">
<title> gobang </title>
<style>
* {

margin: 0px;
padding: 0px;
}
.box {

border-spacing: 0px;
border: 1px solid #3c3c3c;
background-color: #e1e1e2;
margin: auto;
}
.piece {

border-spacing: 0px;
border: 1px solid;
}
</style>
</head>
<body>
<script type="text/javascript" src="./Gobang.js"></script>
</body>
</html>

2.JavaScript part

var ScreenWidth = {

documentWidth: 500,
containerWidth: 400, // Default container width 
cellWidth: 20 // Cell width 
}
if (document.documentElement.clientWidth < 500) {

ScreenWidth.documentWidth = document.documentElement.clientWidth;
ScreenWidth.containerWidth = ScreenWidth.documentWidth * 0.8;
ScreenWidth.cellWidth = ScreenWidth.containerWidth * 0.05;
}
// Constant 
var reg = /\d{1,2}/g;
var white = []; // Let go of the white seeds 
var black = []; // Put the sunspot 
var tempKey = false; // Judge whether it is black or white 
var notOver = true; // Determine if the game is over 
var tips = " White go "; // Hint to go chess 
var count = 0;// The number of connections 
var bv = false; // Black wins 
var wv = false; // White wins 
var yCanWin = [];// An array stored in the same vertical element 
var xCanWin = [];// The array stored in the same horizontal element 
var xyCanWin = [];// The same positive oblique storage array 
var yxCanWin = [];// The same skew storage array 
// Use a timer to listen for victory 
var time = setInterval(function () {

if (bv) {

tips = " Black wins ";
document.getElementsByTagName("span")[0].innerText = tips;
for (var i = 0; i < document.getElementsByClassName("pieceBox").length; i++) {

document.getElementsByClassName("pieceBox")[i].onclick = null;
}
clearInterval(time);
}
if (wv) {

tips = " White wins ";
document.getElementsByTagName("span")[0].innerText = tips;
for (var i = 0; i < document.getElementsByClassName("pieceBox").length; i++) {

document.getElementsByClassName("pieceBox")[i].onclick = null;
}
clearInterval(time);
}
}, 100);
newGame();// Start the game 
function newGame() {

if (document.getElementsByTagName("table").length) {

for (var i = 0; i < document.getElementsByTagName("table").length; i++) {

document.getElementsByTagName("table")[i].remove();
}
}
// Initialize the following 
bgInit();
pieceInit();
spanFn();
white = [];
black = [];
tempKey = false;
notOver = true;
tips = " White go ";
count = 0;
bv = false;
xCanWin = [];
yCanWin = [];
xyCanWin = [];
yxCanWin = [];
}
function spanFn() {

var span = document.createElement("span");
document.body.insertBefore(span, document.getElementsByTagName("script")[0]);
span.innerText = tips;
}
// Board initialization 
function bgInit() {

var table = document.createElement("table");
table.className = "box"
for (var y = 0; y < 20; y++) {

var tr = document.createElement("tr");
for (var x = 0; x < 20; x++) {

var td = "<td class='box-" + y + "-" + x + "' style='width: " + ScreenWidth.cellWidth + "px; height: " + ScreenWidth.cellWidth + "px;border:1px solid #9c9c9c'></td>";
tr.innerHTML += td;
}
table.appendChild(tr);
}
document.body.insertBefore(table, document.getElementsByTagName("script")[0]);
}
// Chess initialization 
function pieceInit() {

var table = document.createElement("table");
table.className = "piece"
table.style = "position: absolute; top: 0; left:50%; margin-left:-" + (ScreenWidth.containerWidth + 42) / 2 + "px";
for (var y = 0; y < 20; y++) {

var tr = document.createElement("tr");
for (var x = 0; x < 20; x++) {

var td = "<td class='piece-" + y + "-" + x + " pieceBox' style='width: " + ScreenWidth.cellWidth + "px; height: " + ScreenWidth.cellWidth + "px;border:1px solid transparent;border-radius: 50%;'></td>";
tr.innerHTML += td;
}
table.appendChild(tr);
}
document.body.insertBefore(table, document.getElementsByTagName("script")[0]);
}
// Go to chess 
for (var i = 0; i < document.getElementsByClassName("pieceBox").length; i++) {

document.getElementsByClassName("pieceBox")[i].onclick = function () {

if (tempKey) {

this.style.backgroundColor = "#000";// The spots 
tempKey = false;
black.push(this.className.match(reg));
victory(black, 0);// Judge whether black wins or not 
if (notOver) {

tips = tipsGo(tempKey);
document.getElementsByTagName("span")[0].innerText = tips;
}
} else {

this.style.backgroundColor = "#fff";// An albino 
tempKey = true;
white.push(this.className.match(reg));
victory(white, 1);// Judge whether white wins or not 
if (notOver) {

tips = tipsGo(tempKey);
document.getElementsByTagName("span")[0].innerText = tips;
}
}
this.onclick = null;// Click after cancel click event 
}
}
// The hint is black or white 
function tipsGo(tempKey) {

if (tempKey) {

return " Go black ";
} else {

return " White go ";
}
}
/**
* Judge how to win
*x It stands for coordinate ,y Represents the ordinate
*1. Win , Namely x Same value , take y Values are sorted and compared
*2. Win , Namely y Same value , take x Values are sorted and compared
*3. It's a slanting win ,x+y The same value , take x or y Compare after sorting
*4. Anti skew wins ,x-y The same value , take x or y Compare after sorting
*/
function victory(target, c) {

if (target.length >= 5) {

// 1. Win yCanWin
for (var i = 0; i < target.length; i++) {

for (var j = 0; j < target.length; j++) {

if (target[j][1] == target[i][1]) {

yCanWin.push(target[j]);// hold x The same values are put into the array yCanWin
}
}
yWin(yCanWin, c);
yCanWin = [];
}
// 2. Win xCanWin
for (var m = 0; m < target.length; m++) {

for (var n = 0; n < target.length; n++) {

if (target[n][0] == target[m][0]) {

xCanWin.push(target[n]);// hold y The same values are put into the array xCanWin
}
}
xWin(xCanWin, c);
xCanWin = [];
}
// 3. It's a slanting win xyCanWin( From bottom left to top right )
for (var a = 0; a < target.length; a++) {

for (var b = 0; b < target.length; b++) {

if (parseInt(target[b][0]) + parseInt(target[b][1]) == parseInt(target[a][0]) + parseInt(target[a][1])) {

xyCanWin.push(target[b])
}
}
yWin(xyCanWin, c);
xyCanWin = [];
}
// 4. Anti skew wins yxCanWin( From top left to bottom right )
for (var v = 0; v < target.length; v++) {

for (var w = 0; w < target.length; w++) {

if (parseInt(target[w][0]) - parseInt(target[w][1]) == parseInt(target[v][0]) - parseInt(target[v][1])) {

yxCanWin.push(target[w])
}
}
xWin(yxCanWin, c);
yxCanWin = [];
}
}
}
// The vertical winning conditions of chess ( The positive and oblique winning conditions of chess )
function yWin(yCanWin, c) {
 // c = 0 For the black man c = 1 On behalf of Baizi 
var sortArray = [];// Sort array 
for (var i = 0; i < yCanWin.length; i++) {

sortArray.push(yCanWin[i][0]);
}
sortArray.sort(function (x, y) {

return x - y;
});
// After array sorting , The first number is compared with the last number plus one ( Note the conversion of numeric types )
for (var j = 0; j < sortArray.length; j++) {

if (sortArray[j + 1]) {

if (parseInt(sortArray[j]) + 1 == parseInt(sortArray[j + 1])) {

count++; // Add one for each continuous , Clear one discontinuity 
if (count == 4 && c == 0) {

bv = true;
notOver = false;// Game over 
return;
} else if (count == 4 && c == 1) {

wv = true;
notOver = false;
return;
}
} else {

count = 0;
}
}
}
count = 0;
}
// The winning conditions of chess ( The anti skew winning condition of chess )
function xWin(xCanWin, c) {

var sortArray = [];
for (var i = 0; i < xCanWin.length; i++) {

sortArray.push(xCanWin[i][1]);
}
sortArray.sort(function (x, y) {

return x - y;
});
for (var j = 0; j < sortArray.length; j++) {

if (sortArray[j + 1]) {

if (parseInt(sortArray[j]) + 1 == parseInt(sortArray[j + 1])) {

count++;
if (count == 4 && c == 0) {

bv = true;
notOver = false;
return;
} else if (count == 4 && c == 1) {

wv = true;
notOver = false;
return;
}
} else {

count = 0;
}
}
}
count = 0;
}

It's not easy to write , Especially judging the conditions for a long time , Like and focus on , Thank you !

版权声明
本文为[osc_xsd7kks3]所创,转载请带上原文链接,感谢

  1. 【计算机网络 12(1),尚学堂马士兵Java视频教程
  2. 【程序猿历程,史上最全的Java面试题集锦在这里
  3. 【程序猿历程(1),Javaweb视频教程百度云
  4. Notes on MySQL 45 lectures (1-7)
  5. [computer network 12 (1), Shang Xuetang Ma soldier java video tutorial
  6. The most complete collection of Java interview questions in history is here
  7. [process of program ape (1), JavaWeb video tutorial, baidu cloud
  8. Notes on MySQL 45 lectures (1-7)
  9. 精进 Spring Boot 03:Spring Boot 的配置文件和配置管理,以及用三种方式读取配置文件
  10. Refined spring boot 03: spring boot configuration files and configuration management, and reading configuration files in three ways
  11. 精进 Spring Boot 03:Spring Boot 的配置文件和配置管理,以及用三种方式读取配置文件
  12. Refined spring boot 03: spring boot configuration files and configuration management, and reading configuration files in three ways
  13. 【递归,Java传智播客笔记
  14. [recursion, Java intelligence podcast notes
  15. [adhere to painting for 386 days] the beginning of spring of 24 solar terms
  16. K8S系列第八篇(Service、EndPoints以及高可用kubeadm部署)
  17. K8s Series Part 8 (service, endpoints and high availability kubeadm deployment)
  18. 【重识 HTML (3),350道Java面试真题分享
  19. 【重识 HTML (2),Java并发编程必会的多线程你竟然还不会
  20. 【重识 HTML (1),二本Java小菜鸟4面字节跳动被秒成渣渣
  21. [re recognize HTML (3) and share 350 real Java interview questions
  22. [re recognize HTML (2). Multithreading is a must for Java Concurrent Programming. How dare you not
  23. [re recognize HTML (1), two Java rookies' 4-sided bytes beat and become slag in seconds
  24. 造轮子系列之RPC 1:如何从零开始开发RPC框架
  25. RPC 1: how to develop RPC framework from scratch
  26. 造轮子系列之RPC 1:如何从零开始开发RPC框架
  27. RPC 1: how to develop RPC framework from scratch
  28. 一次性捋清楚吧,对乱糟糟的,Spring事务扩展机制
  29. 一文彻底弄懂如何选择抽象类还是接口,连续四年百度Java岗必问面试题
  30. Redis常用命令
  31. 一双拖鞋引发的血案,狂神说Java系列笔记
  32. 一、mysql基础安装
  33. 一位程序员的独白:尽管我一生坎坷,Java框架面试基础
  34. Clear it all at once. For the messy, spring transaction extension mechanism
  35. A thorough understanding of how to choose abstract classes or interfaces, baidu Java post must ask interview questions for four consecutive years
  36. Redis common commands
  37. A pair of slippers triggered the murder, crazy God said java series notes
  38. 1、 MySQL basic installation
  39. Monologue of a programmer: despite my ups and downs in my life, Java framework is the foundation of interview
  40. 【大厂面试】三面三问Spring循环依赖,请一定要把这篇看完(建议收藏)
  41. 一线互联网企业中,springboot入门项目
  42. 一篇文带你入门SSM框架Spring开发,帮你快速拿Offer
  43. 【面试资料】Java全集、微服务、大数据、数据结构与算法、机器学习知识最全总结,283页pdf
  44. 【leetcode刷题】24.数组中重复的数字——Java版
  45. 【leetcode刷题】23.对称二叉树——Java版
  46. 【leetcode刷题】22.二叉树的中序遍历——Java版
  47. 【leetcode刷题】21.三数之和——Java版
  48. 【leetcode刷题】20.最长回文子串——Java版
  49. 【leetcode刷题】19.回文链表——Java版
  50. 【leetcode刷题】18.反转链表——Java版
  51. 【leetcode刷题】17.相交链表——Java&python版
  52. 【leetcode刷题】16.环形链表——Java版
  53. 【leetcode刷题】15.汉明距离——Java版
  54. 【leetcode刷题】14.找到所有数组中消失的数字——Java版
  55. 【leetcode刷题】13.比特位计数——Java版
  56. oracle控制用户权限命令
  57. 三年Java开发,继阿里,鲁班二期Java架构师
  58. Oracle必须要启动的服务
  59. 万字长文!深入剖析HashMap,Java基础笔试题大全带答案
  60. 一问Kafka就心慌?我却凭着这份,图灵学院vip课程百度云