About saving batch data into MySQL

Willow rustling 2020-11-09 13:19:45
saving batch data mysql

A request made :

Generate 13 The card number of digit only number and 8 It's a bit pure digital Carmi , The card number and the card number must be unique , Then save to mysql.

Ideas :

1. First mysql Set the two fields to a unique index , Ensure that the values of these two fields are unique in the table

2. Card numbers are growing in an orderly way , Easy to implement , First query the maximum value of this field in the database , And then growth generation

3. Carmel is out of order , It's difficult to achieve ,( Search online and run the results many times , It is found that the repetition rate of random numbers is the lowest , So random generation is chosen ), Query the database for this field , Put the field in map in ( In order to judge when generating a Carmi , Whether the Carmel exists ) Every time the generation is unique , Will put the value in the map, The generated carmie is put into linedklist in ( Because it's a frequent add operation ,linkedlist Performance ratio arraylist High performance )

4. Loop through the card number ( The card number and the number of cards are the same ), And then generate the saved object , Put in list in

5. again saveAll() Method ( Because of the use of springdatajpa, The saveAll() The source code is to cycle through the data and then save it one by one , Used jpa Batch save configuration for , There is not much difference between setting and not configuring ), Preservation .

Code :

service Layer method

protected EntityManager entityManager;
public List<PayGeneralCard> add(PayGeneralCardFormBean formBean){
// Verify the current spAppId Whether it is valid or not
PayServiceProvider provider = payServiceProviderService.checkSpAppIdAndState(formBean.getSpAppId());
if(null == provider){
return null;
// Get the maximum batch number of the current application
int maxBatchNumber = findMaxBatchNumber(formBean.getSpAppId());
// Get the largest card number
Long byMaxCardNumber = findByMaxCardNumber();
// Get all the card numbers , Because it was written sql Query so the data type becomes BigInteger, It's going to turn into Long
List<BigInteger> cardPasswordfindAll = payGeneralCardDao.cardPasswordfindAll();
HashMap<String, Boolean> map = new HashMap<>();
List<Long> cardPasswords = cardPasswordfindAll.stream().map(item-> item.longValue()).collect(Collectors.toList());
for(Long cardPassword:cardPasswords){
// Generate card number
ArrayList<Long> cardNumbers = PayCardNumberUtil.createNumber(formBean.getCount(), byMaxCardNumber);
// Generating Carmi
LinkedList<Long> passwords = PayCardPassWordUtil.createPassword(formBean.getCount(),map);
// Assembly data
LinkedList<PayGeneralCard> list = new LinkedList<>();
for(int i = 0;i<cardNumbers.size();i++){
PayGeneralCard bean = createBean(formBean.getSpAppId(), formBean.getType(), cardNumbers.get(i),
passwords.get(i), maxBatchNumber);
// Save the data
List<PayGeneralCard> payGeneralCards = savaAll(list);
return payGeneralCards;


// Batch add data 
public List<PayGeneralCard> savaAll(List<PayGeneralCard> payGeneralCards){
ArrayList<PayGeneralCard> list = new ArrayList<>(16);
for(PayGeneralCard payGeneralCard : payGeneralCards){
return list;

import java.util.ArrayList;
public class PayCardNumberUtil {
private static long seq = 1000000000000l;
private static final long ROTATION = 9999999999999l;
public static synchronized long next() {
if (seq > ROTATION) seq = 1000000000000l;
return seq++;
* How to generate the card number of all in one card
* @param count Total number of builds
* @param startNumber From this number to the next generation
* @return
public static ArrayList<Long> createNumber(long count,long startNumber){
if(seq < startNumber){
seq = startNumber;
ArrayList<Long> list = new ArrayList<>();
for (int i = 0; i < count; i++) {
long next = PayCardNumberUtil.next();
return list;
public static void main(String[] args) {
System.out.println(PayCardNumberUtil.createNumber(10l, 2004000000057l));

import java.util.*;
* All in one card password generator
* @author nature
* @create 2017-12-22 10:58
public class PayCardPassWordUtil {
public static LinkedList<Long> createPassword(Long count,Map<String, Boolean> map){
LinkedList<Long> list = new LinkedList<>();
for (int i = 0; i < count; i++) {
String number = generateUID(map);
return list;
// The only way to test without repetition
public static String generateUID(Map<String, Boolean> map){
Random random = new Random();
String result="";
for(int i=0;i<8;i++){
// The initial cannot be 0
result += (random.nextInt(9)+1);
// If there is a value, it means that the card has already existed , Need to regenerate
if(null != map.get(result)){
return generateUID(map);
return result;
public static void main(String[] args) {
Map<String, Boolean> map = new HashMap<String, Boolean>();
for (int i = 0; i < 1000; i++) {

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